Samstag, 8. Mai 2010

Leistungsaufgabe von http://www.edhelper.com

image

(%i3) jason:2*60+16;
sydney:60+26;
(%o3) 136
(%o4) 86
(%i5) g:1/jason+1/sydney=1/dauer;
(%o5) 111/5848=1/dauer
(%i6) l:solve(g,dauer),numer;
rat: replaced 0.018980848153215 by 111/5848 = 0.018980848153215
rat: replaced 0.018980848153215 by 111/5848 = 0.018980848153215
rat: replaced 1.7099863201094391E-4 by 1/5848 = 1.7099863201094391E-4
rat: replaced -52.6846846846847 by -5848/111 = -52.6846846846847
(%o6) [dauer=52.68468468468468]
(%i7) dauer:ev(dauer,l);
(%o7) 52.68468468468468
(%i8) dauer:floor(dauer+0.5);
(%o8) 53

0 Kommentare:

Kommentar veröffentlichen

Leser

Blog-Archiv